11,9g of potassium bromide dissolved in 3dm³ of solution

1 answer

To find the concentration of potassium bromide (KBr) in the solution, you need to follow these steps:

  1. Calculate the number of moles of KBr:

    • First, find the molar mass of KBr:

      • Potassium (K) has an atomic mass of approximately 39.1 g/mol.
      • Bromine (Br) has an atomic mass of approximately 79.9 g/mol.
      • Therefore, the molar mass of KBr = 39.1 g/mol + 79.9 g/mol = 119.0 g/mol.
    • Now calculate the number of moles of KBr in 11.9 g: \[ \text{Moles of KBr} = \frac{\text{Mass}}{\text{Molar Mass}} = \frac{11.9 , \text{g}}{119.0 , \text{g/mol}} \approx 0.100 , \text{mol} \]

  2. Calculate the concentration in mol/dm³ (Molarity):

    • To find the concentration (C) in moles per cubic decimeter (mol/dm³), use the formula: \[ C = \frac{\text{Moles of solute}}{\text{Volume of solution in dm}^3} \]
    • Here the volume of the solution is given as 3 dm³: \[ C = \frac{0.100 , \text{mol}}{3 , \text{dm}^3} \approx 0.0333 , \text{mol/dm}^3 \]

Thus, the concentration of the potassium bromide solution is approximately 0.0333 mol/dm³.