In this genetic cross, we have a mother who is homozygous for normal blood clotting (XHXH) and a father who is heterozygous for hemophilia (XHY). The allele for hemophilia is recessive (h).
The potential alleles from the mother (XHXH) can only provide XH, and the potential alleles from the father (XHY) can provide either XH or Y.
Here’s the Punnett square for the cross between XHXH (mother) and XHY (father):
XH | Y
-------------
XH | XHXH | XHY
XH | XHXH | XHY
From this Punnett square, we can see the possible genotypes of the offspring:
- XHXH (female, normal blood clotting)
- XHY (male, normal blood clotting)
Since all offspring will have either XHXH or XHY, there are no offspring that can inherit the hemophilia allele (h) because the mother does not carry the hemophilia allele (h).
Thus, the probability that any of their offspring will have hemophilia is 0 out of 4, which translates to 0% probability.
Therefore, the answer is none of the options provided (1/4, 2/4, 3/4, 4/4) is correct. The correct answer should be 0/4 (none of the offspring will have hemophilia).