Look up the specific heats of Cu, Al and ethyl alcohol. Call them Cc, Ca and Ce.
The heat lost by the Al PLUS the heat lost by the Cu equals the heat gained by the alcohol.
Write that as an equation and solve for the initial T(alcohol). (Call it T)
11*Ca(200 - 25) + 20*Cc(T-25) = 54*Ce*(25 -15)
You do the rest.
11.0 g of aluminum at 200C and 20.0 g of copper are dropped into 54.0 of ethyl alcohol at 15C. The temperature quickly comes to 25.0. What was the initial temperature of the copper?
1 answer
1 answer