To find the number of moles of Sn(NO3)2 in 0.0087 mL of the solution, we need to convert the volume to liters and then multiply by the molarity:
0.0087 mL = 0.0087 L
Number of moles of Sn(NO3)2 = 0.0087 L * 0.400 mol/L = 0.00348 mol
Therefore, there are 0.00348 moles of Sn(NO3)2 in 0.0087 mL of the solution.
10Sn2+(aq) + 5MnO4-(aq) + 16H+(aq) → 10Sn4+(aq) + 5Mn2+(aq) + 8H2O(l)
0.400 mol/L solution of Sn(NO3)2 (aq) was titrated with an acidified KMnO4(aq).
Volume of Sn(NO3)2 is 0.0087mL
1 answer