10ml 15% HCl + 5g NaHCO3 = NaCl + CO2 + H2O. How much CO2 [L]

Answer 1

This is a limiting reagent (LR) problem. You know that because amounts are given for BOTH reactants.
Is that 10% w/v HCl? If so then you have 10 g HCl/100 mL or 1.0 g HCl/10 mL.
mols HCl = grams/molar mass = 1.0/36.5 = ?
mols NaHCO3 = grams/molar mass -= ?

HCl + NaHCO3 ==> NaCl + H2O + CO2

Using the coefficients in the balanced equation, convert mols HCl to mols CO2.
Do the same for mols NaHCO3 to mol CO2.
It is likely that these two values will not agree which means one of them is not right; the correct value in LR problems is ALWAYS the smaller value and the reagent producing that value is the LR.

Now convert the smaller value to L.
mols CO2 x 22.4 L/mol = ? L CO2