Asked by ken
10L of hard water required 5.6g of line for removing hardness. Hence temporary hardness in ppm of cac03.
The answer 1000
ppm= 1mg/1L
cac03 = 100 g/mol
who solve it for me clearly step by step
Thank a lot all tutors
The answer 1000
ppm= 1mg/1L
cac03 = 100 g/mol
who solve it for me clearly step by step
Thank a lot all tutors
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