C3H8O3 + 5O2 >>> 3CO2 + 4H2O
well, let 10cm^3 be one part.
you have in the reaction one part propane, five parts O2 used, and you created 7 parts (carbon dioxide and steam) product.
so of the 60cm^3 original O2, 50cm^3 was used in the reaction, so one part is left over:
residual gasses: (60-50)cm^3 + 7(10cm^3)= ....
10cm3 of propane was sparked with 60cm3 of oxygen at Stp.What is the volume of residual gases after the reaction is cooled.
2 answers
oops! Propane is C3H8
.............C3H8 + 5O2 ==> 3CO2 + 4H2O
.............C3H8 + 5O2 ==> 3CO2 + 4H2O