Without calculation my gut feeling is that 148 tables is WAY too many. You must be getting a kick back from the antacid company.
How much acid do you have to neutralize? That's pH = -log(H^+) = 1.1 = -log(H^+) and (H^+) = 0.0794
millimols acid in stomach is 140 mL x 0.0794 = 11.1 mmols.
mmols tablet can neutralize is 25.82 x 0.200 = 5.16 (but you have TWO equivalence points here. Which one is the 25.82 mL? I have assumed that the titration is the same for both and made no correction for the 2HCl/1 mol CaCO3)) I will assume you titrated to the second equivalence point.
So you need two tablets. You can put 146 of those you counted out and put them back in the bottle. 11.1/5.16 = 2.15 tablets but I would give just two and let it go at that.
The balanced equation is
CaCO3 + 2HCl ==> CaCl2 + H2O + CO2
Imagine that you are a charge nurse in a nursing home. You are typically the only medical personnel in the house at any one time. A patient who is known to have excess stomach acid asks you to give him an antacid tablet. The typical antacid is either calcium carbonate or magnesium carbonate. The antacid tablet that you stock requires 25.82 mL of 0.200 M HCl to titrate to its equivalence point. Assume that stomach acid has a pH of 1.1. Also, suppose that the patient’s size and weight indicate that his stomach will hold approximately 140 mL of stomach acid.
• How many antacid tablets should you give him if you want to neutralize all his stomach acid?
I came up with 148.836 on this one. Is that correct?
• Explain your rationale for your answer. Include the balanced equation you used to determine your answer.
Not sure where to begin on this one.
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