F(x) = 403cos(12.9) + 403cos(12.9)
F(y) = 403sin(12.9) - 403sin(12.9)
F(x) = 806cos(12.9) = 761.56 N
F(y) = 0 N
Thus, the overall force vector would be 761.56 N at 0 degrees.
A barge is hauled along a straight-line section of canal by two horses harnessed to tow ropes and walking along the tow paths on either side of the canal. Each horse pulls with a force of 403 N at an angle of 12.9° with the centerline of the canal. Find the sum of the two forces exerted by the horses on the barge.
2 answers
F(x) = 403cos(12.9) + 403cos(12.9)
F(y) = 403sin(12.9) - 403sin(12.9)
F(x) = 806cos(12.9) = 761.56 N
F(y) = 0 N
Thus, the overall force vector would be 761.56 N at 0 degrees.
or 7.6156kN
F(y) = 403sin(12.9) - 403sin(12.9)
F(x) = 806cos(12.9) = 761.56 N
F(y) = 0 N
Thus, the overall force vector would be 761.56 N at 0 degrees.
or 7.6156kN
2 answers