2x 4 12 (2-x)
--- / ---- + ---- X ---
(x^2-4) (x^2-4x+4) (x^2-4) 3
5 answers
You aren't following instructions very well. LOOK AT YOUR POST and you will see that you can't space it this way. Look back at your original post for my suggestion on how to post a problem of this kind. We can't help if we can't make heads or tails of the question.
ok ill do it like this ...
2x over x squared - 4 divided by 4 over x squared - 4x + 4 plus 12 over x squared - 4 multiplied by 2-x over 3
2x over x squared - 4 divided by 4 over x squared - 4x + 4 plus 12 over x squared - 4 multiplied by 2-x over 3
Is this it? And what do you want to do with it?
{[2x/(x^2-4)]/(4/x^2-4x+4)} + [12/(x^2-4)]*[(2-x)/3]
{[2x/(x^2-4)]/(4/x^2-4x+4)} + [12/(x^2-4)]*[(2-x)/3]
yess that's it .. it has to be expressed in simplest form - im sorry for the misunderstanding thank you very much for any help that you can give
Since you agreed with DrBob's way of writing your problem, let's take it in parts
The first term reduces to
[2x/((x+2)(x-2))]*[(x-2)(x-2)/4
= x(x-2)/[2(x+2)]
the second term [12/(x^2-4)]*[(2-x)/3]
= 12/[(x-2)(x+2)]*(2-x)/3
= -4/(x+2)
using a common denominator of 2(x+2)
we get :
= (x^2 - 2x - 4)/[2(x+2)]
= (x-4)(x+2)/[2(x+2)]
= (x-4)/2 , x cannot be -2
The first term reduces to
[2x/((x+2)(x-2))]*[(x-2)(x-2)/4
= x(x-2)/[2(x+2)]
the second term [12/(x^2-4)]*[(2-x)/3]
= 12/[(x-2)(x+2)]*(2-x)/3
= -4/(x+2)
using a common denominator of 2(x+2)
we get :
= (x^2 - 2x - 4)/[2(x+2)]
= (x-4)(x+2)/[2(x+2)]
= (x-4)/2 , x cannot be -2