Stella is recording temperatures every day for 5 days. On the first day, Stella recorded a temperature of 0 degrees Farenheit. A. On the second day, the temperature was 3 degrees Fahrenheit above the temperature on the first day. What was the temperature on the second day? B. On the third day, it was 4 degrees Fahrenheit below the temperature of the first day. What was the temperature? C. The temperature on the fourth day was the opposite of the temperature on the second day. What was the temperature? D. The temperature on the fifth day was the absolute value of the temperature on the fourth day. What was the temperature? E. Write the temperatures in order from least to greatest. F. What is the difference in temperature between the coldest day and the warmest day? Can you please help answer A through F questions, total of 6 answers thanks so much
50 answers
A. 0 + 3 = 3 (2nd)
B. 0 - 4 = -4 (3rd)
C. -3 (4th)
D. 3 (5th)
With this information, you should be able to answer E and F yourself.
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Temperature
(°F) 50 42 31 62 51 55 45
Once a day for seven days, Melanie recorded the temperature (in °F) of a stream near her home. make a box plot
1. Calculate the five number summary: minimum, first quartile (Q1), median (Q2), third quartile (Q3), and maximum.
- Minimum: 31
- Q1: 44 (average of 42 and 45, the two values closest to the first quartile)
- Q2 (median): 50.5 (average of 50 and 51, the two values closest to the median)
- Q3: 58.5 (average of 55 and 62, the two values closest to the third quartile)
- Maximum: 62
2. Draw a number line that spans the range of the data set (from 31 to 62).
3. Draw a box that spans from Q1 to Q3.
4. Draw a vertical line inside the box at the median (Q2).
5. Draw whiskers from the edge of the box to the minimum and maximum.
6. Plot any outliers (values that are more than 1.5 times the interquartile range, or IQR, beyond the nearest quartile) as individual points.
The resulting box plot for these data would look something like this:
```
| *
| * |
| | |
| | |
| | |
|______________|_|__
30 40 50 60 70 (°F)
```
Note that no outliers were identified in this data set.
12, 9, 11, 8, 9, 12, 9
1. Add up all the numbers: 12 + 9 + 11 + 8 + 9 + 12 + 9 = 70
2. Divide the sum by the total number of values (which is 7): 70 / 7 = 10
Therefore, the mean of the numbers 12, 9, 11, 8, 9, 12, 9 is equal to 10.
State High, Degrees F Low, Degrees F
Alabama 82 56
Arkansas 80 55
Florida 87 65
Georgia 88 64
Kentucky 78 55
Alaska 72 44
Michigan 81 54
Tennessee 79 55
Hawaii 84 68
Using the table, find the RANGE of the average low temperatures for the states listed in the chart.
Responses
A 24
B 14
C 112
D 81
To find the range of the average low temperatures for the states listed in the chart, we need to determine the lowest and highest average low temperatures among these states and then find the difference between them.
The average low temperatures for these states are:
- Alabama: 56°F
- Arkansas: 55°F
- Kentucky: 55°F
- Michigan: 54°F
- Tennessee: 55°F
The lowest average low temperature is 54°F (Michigan) and the highest is 56°F (Alabama).
Therefore, the range of the average low temperatures for the states listed in the chart is:
56 - 54 = 2
So the answer is not listed among the choices provided.
"El Shinö Li Pope" and "yen" are both terms from the language of the "Gaster's Followers", a fan-made community associated with the video game Undertale. The phrase "six calico yen" appears to be a non sequitur, as it does not relate to anything in the game or the community.
In other words, "six calico yen" is not a meaningful phrase in any language or context, and does not convey a coherent thought or idea. It appears to be a random set of words that has no particular significance or relevance.
If you have more information or a specific question regarding "Shino" or someone from Europe, I would be happy to assist you further.
Here are the steps to calculate the range of a data set:
1. Write down the values in the data set.
2. Identify the smallest value in the data set.
3. Identify the largest value in the data set.
4. Subtract the smallest value from the largest value. The result is the range.
Here's an example:
Data set: 10, 12, 6, 8, 20
1. The values in the data set are: 10, 12, 6, 8, 20
2. The smallest value in the data set is 6.
3. The largest value in the data set is 20.
4. Subtract the smallest value from the largest value: 20 - 6 = 14.
Therefore, the range of the data set 10, 12, 6, 8, 20 is 14.
Jennifer's recent golf scores are shown. What is her mean score, rounded to the nearest tenth?
1. Add up all the scores: 72 + 80 + 74 + 68 + 65 + 66 + 72 + 70 + 65 + 80 + 75 = 747
2. Divide the sum by the total number of values (which is 11): 747 / 11 = 67.9 (rounded to the nearest tenth)
Therefore, Jennifer's mean golf score, rounded to the nearest tenth, is 67.9.
1. Determine the number of decimal places you want to round to.
2. For each value in the data set, look at the digit in the next decimal place that is one position to the right of the desired rounding position.
3. If this digit is 5 or greater, then round up the digit in the desired position. If this digit is less than 5, then leave the digit in the desired position unchanged.
4. Repeat this process for each value in the data set.
Here's an example:
Data set: 1.845, 2.306, 1.224, 3.372, 2.876
To round this data set to two decimal places, we follow the above steps:
1. We want to round to two decimal places.
2. For 1.845, the digit in the third decimal place is 5, so we round up the digit in the second decimal place to obtain 1.85. For 2.306, the digit in the third decimal place is 6, so we round up the digit in the second decimal place to obtain 2.31. Similarly, we round 1.224 to 1.22, 3.372 to 3.37, and 2.876 to 2.88.
3. The resulting rounded data set is: 1.85, 2.31, 1.22, 3.37, 2.88.
Therefore, we have rounded the data set to two decimal places.
1. Identify the digit in the hundredth place. This is the third digit to the right of the decimal point, which will be a zero in this case since there are no decimals.
2. Identify the digit in the tenths place. This is the second digit to the right of the decimal point, which in this case, doesn't exist.
3. Determine which direction to round by looking at the digit in the ones place. If the digit in the ones place is 5 or greater, you round up to the next tenth. If it's less than 5, then you round down.
4. Replace the remaining digits (after the tenth place) with zeros.
Here is an example:
Data set: 18, 22, 17, 11, 15, 13, 20
1. There is no hundredth place to identify, as there are no decimals.
2. There is no tenths place to identify.
3. For the first number, 18, since the digit in the ones place (8) is greater than 5, you round up to 20.
For the second number, 22, since the digit in the ones place (2) is less than 5, you round down to 20.
For the third number, 17, since the digit in the ones place (7) is greater than 5, you round up to 20.
For the fourth number, 11, since the digit in the ones place (1) is less than 5, you round down to 10.
For the fifth number, 15, since the digit in the ones place (5) is exactly 5, you round up to 20.
For the sixth number, 13, since the digit in the ones place (3) is less than 5, you round down to 10.
For the seventh number, 20, there is no need to round as it is already a multiple of 10.
4. After rounding, the data set becomes: 20, 20, 20, 10, 20, 10, 20
Therefore, rounding these numbers to the nearest tenth gives us the new data set: 20, 20, 20, 10, 20, 10, 20.
round this data set to one number and round to the nearest tenth
1. For each number in the data set, look at the digit in the tenths place (second digit to the right of the decimal point).
2. If the digit in the hundredths place (third digit to the right of the decimal point) is 5 or greater, round up the digit in the tenths place. If it is less than 5, leave the digit in the tenths place unchanged.
3. If there is no digit in the tenths place, simply insert a decimal point followed by a zero.
4. Repeat this process for each number in the data set.
To round this data set to one decimal place, the resulting rounded data set is:
71.8, 79.5, 73.5, 68.0, 65.0, 66.0, 71.5, 70.0, 65.0, 79.5, 75.0.
Therefore, rounding this data set to one decimal place gives us the new data set: 71.8, 79.5, 73.5, 68.0, 65.0, 66.0, 71.5, 70.0, 65.0, 79.5, 75.0.
1. Look at the digit in the hundredths place, which is 2.
2. Look at the digit in the tenths place, which is 7.
3. Since the digit in the hundredths place is less than 5, we do not need to round up.
4. To round to the nearest tenth, we leave the digit in the tenths place (7) unchanged, and all digits to the right of it become 0s.
5. Therefore, the rounded number is 71.7 (rounded to one decimal place).
Therefore, rounding 71.727 to the nearest tenth gives us the rounded value of 71.7.
order least to greatest
{53, 53, 57, 59, 60, 66, 66, 68, 69, 70, 71, 75, 75, 77, 78, 82}
Therefore, the ordered list from least to greatest is:
53, 53, 57, 59, 60, 66, 66, 68, 69, 70, 71, 75, 75, 77, 78, 82.
{66, 66, 71, 78, 57, 53, 69, 68, 70, 60, 59, 55, 75, 82, 77, 53}
{66, 66, 71, 78, 57, 53, 69, 68, 70, 60, 59, 55, 75, 82, 77, 53}
{66, 66, 71, 78, 77, 53, 69, 68, 70, 60, 59, 55, 75, 82, 77, 53}
{66, 66, 71, 78, 77, 53, 69, 68, 70, 60, 59, 55, 75, 82, 77, 53}
{66, 66, 71, 58, 57, 53, 69, 68, 70, 60, 59, 55, 75, 82, 77, 53}
order least to greatest