Question
The perimeter of a triangle is 195 mm.If the lengths of the sides are consecutive odd integers,find the length of each side.
what steps do i need to do in order to get the answre?
Perimeter= L + L+2 + L+4
solve for L. That is the short side. THen add two for the next side, and add two again for the last side.
x = first odd integer
x + 2 = second odd integer
x + 4 = third odd integer
Therefore:
x + x + 2 + x + 4 = 195
Solve for x. Don't forget to list all sides!
I hope this will help get you started.
what steps do i need to do in order to get the answre?
Perimeter= L + L+2 + L+4
solve for L. That is the short side. THen add two for the next side, and add two again for the last side.
x = first odd integer
x + 2 = second odd integer
x + 4 = third odd integer
Therefore:
x + x + 2 + x + 4 = 195
Solve for x. Don't forget to list all sides!
I hope this will help get you started.
Answers
3x+6=195
-6 -6
3x=189
divide by 3
on both sides
and you get x=63
-6 -6
3x=189
divide by 3
on both sides
and you get x=63
Mohammed
Related Questions
Perimeter of a triangle. The perimeter of a triangle is 195 mm. If the lengths of the sides are cons...
the sides of a triangle are consecutive integers.If its perimeter is 126cm.find the lengths of the s...
The three sides of a triangle are consecutive even integers. If the perimeter of the triangle is 72...
One leg of a right triangle has a length of 15 m. The other sides have lengths that are consecutive...