pick some times that meet the criterion
north for 30 seconds, south for 10 seconds , total time = 40 seconds
distance north from start = 25*30
then back 32*10
total distance north (displacement vector, not distance traveled) = 25*30 - 32*10
so
Vaverage = (25*30 - 32*10)/40
= (75 - 32)/4
= 10.75 m/s
A car makes a trip due north for three-fourths of the time and due south one-fourth of the time. The average northward velocity has a magnitude of 25 m/s, and the average southward velocity has a magnitude of 32 m/s. Taking northward to be the positive direction, what is the average velocity for the trip?
1 answer
1 answer