A tennis ball is struck and departs from the racket horizontally with a speed of 26.4 m/s. The ball hits the court at a horizontal distance of 18.4 from the racket. How far above the court is the tennis ball when it leaves the racket?

Answer 1

Xo = 26.4 m/s.
Dx = 18.4 m.
Tf = Fall time.

Dx = Xo*Tf = 26.4 * Tf = 18.4 m.
Tf = 0.697 s.

h = 0.5g*Tf^2 = 4.9*0.697^2 = 2.38 m.