Asked by chidera
⦁ An arrow is shot with speed 36.0 m/s at an angle of 24.0° above the horizontal. Assuming the archer was on level ground, find the maximum height and the range.
Answers
Answered by
Henry
Vo = 36m/s[24o]
Xo = 36*cos24 = 32.9 m/s.
Yo = 36*sin24 = 14.64 m/s.
h = (Y^2-Yo^2)/2g = (0-(14.64^2))/-19.6 = 10.94 m.
Xo = 36*cos24 = 32.9 m/s.
Yo = 36*sin24 = 14.64 m/s.
h = (Y^2-Yo^2)/2g = (0-(14.64^2))/-19.6 = 10.94 m.
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