Okay, so! I figured out how to get the Point-slope form to the question I was given which led me to y+3 =-2(x+1), but, now I'm stick on finding the Slope Intercept form to get my answer. Can someone help me? Thanks!

Answer 1

slope intercept form is in the form
y=ax+b

If you start from the equation above, you would isolate (solve for) y in terms of x and the constants, then simplify the right-hand side to remove parentheses.

Isolate y means use algebraic operations to leave only y on the left-hand side.

For example, 2y+1=4x+3
=>
2y = 4x+3-1 (after subtracting 1 from each side)
2y = 4x+1
y=2x+1/2 (after dividing by 2 on each side)
and this is now in slope-intercept form. (2 is the slope, 1/2 is the y intercept if you plot this line in a graph).

Answer 2

@ MathMate,

Here is the original question; Write the equation of the line with slope -2 that passes through the point (-1, -3) in slope-intercept form. But I've tried to figure out how to do it and I'm literally stuck.

Answer 3

I think the easiest way is to use the point-slope form of the equation, since they gave you a point and a slope. Recall that the equation for a line through (h,k) with slope m is

y-k = m(x-h)

So, you have

y+3 = -2(x+1)

Now work with that:

y+3 = -2x-2
y = -2x-5