Question
1.Locate the discontinuity of the function
y=1/(1+sin x)
2.Suppose that f is a continuous function defined for all real numbers x and f(-5)=3 and f(-1)=-2 . If f(x) = 0 for one and only one value of x, then which of the following could be x?
y=1/(1+sin x)
2.Suppose that f is a continuous function defined for all real numbers x and f(-5)=3 and f(-1)=-2 . If f(x) = 0 for one and only one value of x, then which of the following could be x?
Answers
#1: when is the denominator zero? When
1+sinx = 0
sinx = -1
x = 3π/2 + 2kπ
Since f(-5) > 0 and f(-1) < 0, f(x)=0 only for a single value of x between -5 and -1.
I assume the given choices included such a number.
1+sinx = 0
sinx = -1
x = 3π/2 + 2kπ
Since f(-5) > 0 and f(-1) < 0, f(x)=0 only for a single value of x between -5 and -1.
I assume the given choices included such a number.
Related Questions
A function f(x) is said to have a removable discontinuity at x=a if:
1. f is either not defined or...
A function f(x) is said to have a removable discontinuity at x=a if:
1. f is either not defined or...
Suppose
g(x) = { 1 / (x - 2) if x < 1
2x - 4 if x >/= 1
The best description con...
Suppose
g(x)={1/(x-2) if x<1
{2x-3 if x≥1
The best description concerning the continuity o...