Your projectile launching system is partially jammed. It can only launch objects with an initial vertical velocity of 42.0 m/s, though the horizontal component of the velocity can vary. You need your projectile to land 211 m from its launch point. What horizontal velocity do you need to program into the system?

Question

Okay so for this problem I did
211m/ 2(42m/s)/g
I got 24.62 m/s is this correct?

Answer 1

time in air:
vf=vi-gt=42-9.8t in the vertical , vf=-vi
t= 2*42/9.8=84/9.8 figure that out.

horizontal
distance=vh*time
vhoriz=211/time above Looks right.