Asked by S

If 309 J of heat are removed from 10.0 g of ice (specific heat = 2.06 J/g
ºC) at -5.5 ºC, what is the final temperature of the ice sample?
Answered by DrBob222
-q = mass ice x specific heat ice x (Tfinal=Tinitial)
-309 = 10.0 x 2.06 x [Tf -(-5.5)]
Solve for Tf.
Answered by S
Thank you Dr. Bob
Answered by Leila
-20.5
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