Question
The price of a stock, A(x), over a 12-month period decreased and then increased according to the question A(x)= 0.75x2-6x+20, where x equals the number of months. The price of another stock, B(x), increased according to the equation B(x)=2.75x+1.50 over the same 12-month period. Graph and label both equations on the accompanying grid. State all prices, to the nearest dollar, when both stock values were the same.
Answers
drwls
We cannot draw graphs for you here. That is an exercise you should do yourself.
The prices are the same when
0.75 x^2 -6x + 20 = 2.75 x + 150
which can be rewritten
0.75 x^2 -8.75 x -130 = 0
Solve for x using the quadratic equation and use the value(s) of x that you get to calculate the price. Ignore any negative x values
The prices are the same when
0.75 x^2 -6x + 20 = 2.75 x + 150
which can be rewritten
0.75 x^2 -8.75 x -130 = 0
Solve for x using the quadratic equation and use the value(s) of x that you get to calculate the price. Ignore any negative x values
Anonymous
26
Anonymous
$9 and $26
I found this using graphs and intersections.
I found this using graphs and intersections.