Asked by annie
A vehicle starts from rest and accelerates with a constant acceleration, covering 200m in 5s. it then continues at a constant velocity for 300m before decelerating with a constant 2m/s^2 deceleration to a stop. what is the maximum speed attained, total time traveled, total distance covered?
Answers
Answered by
Damon
200 meters in 5 seconds
average speed = 200/5 = 40 m/s
so speed is 80 m/s at 200 m
it slows down after that so 80 is your answer
goes at 80 for 300 m
time = 300/80 = 30/8 = 15/4 seconds between 200 and 500
now from 500 m and 80 m/s, brakes down to zero at -2 m/s^2
0 = 80 - 2 t
t = 40 seconds
so time total = 5 + 15/4 + 40
average speed during braking phase = 40
so from 500 m to stop it covers
40 * 40 =1600 meters
500 + 1600 = 2100 meters total
average speed = 200/5 = 40 m/s
so speed is 80 m/s at 200 m
it slows down after that so 80 is your answer
goes at 80 for 300 m
time = 300/80 = 30/8 = 15/4 seconds between 200 and 500
now from 500 m and 80 m/s, brakes down to zero at -2 m/s^2
0 = 80 - 2 t
t = 40 seconds
so time total = 5 + 15/4 + 40
average speed during braking phase = 40
so from 500 m to stop it covers
40 * 40 =1600 meters
500 + 1600 = 2100 meters total
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.