Asked by Ruby
Given ________, – 243, – 226, – 209, – 192, – 175, …
a. What is the 67th term of the sequence
b. What is the series of the first 27 terms of the sequence
a. What is the 67th term of the sequence
b. What is the series of the first 27 terms of the sequence
Answers
Answered by
Reiny
a = -243
d = -226 - (-243) = 17
term(67) = a + 66d
= -243 + 66(17) = 879
sum(n) = (n/2)(2a + (n-1)d)
sum (27) = (27/2)(-486 + 26(17))
= -594
Here is a nice new part to the question:
For which terms does the sequence switch from negative to positive ?
d = -226 - (-243) = 17
term(67) = a + 66d
= -243 + 66(17) = 879
sum(n) = (n/2)(2a + (n-1)d)
sum (27) = (27/2)(-486 + 26(17))
= -594
Here is a nice new part to the question:
For which terms does the sequence switch from negative to positive ?
Answered by
Reiny
Just looked at the first of the "Related questions" below, which I had answered in June, and realized that your _____ , meant that -243 was actually the second term
I am pretty sure you can make the suitable adjustments.
(your first term will be -260)
I am pretty sure you can make the suitable adjustments.
(your first term will be -260)
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