Question
a car travels east at 89 km/h for 1 hour.it then travels 26 east of north at 141 km/h for another 1 hour.
a)what is the average speed for the trip?
b)what is the average velocity for the trip?
a)what is the average speed for the trip?
b)what is the average velocity for the trip?
Answers
Henry
a. d = 89 + 141km[64o[]CCW.
d = 89 + 141*Cos64 + i141*sin64
d = 89 + 61.8 + 126.7i = 150.8 + 126.7i
= 196.9km[40o]
Speed = d/t = 196.9km/2h = 98.4km/h.
b. V = 196.9km[40o]/2h = 98.4km/h[40o].
= 98.4km/h[50o] E of N.
d = 89 + 141*Cos64 + i141*sin64
d = 89 + 61.8 + 126.7i = 150.8 + 126.7i
= 196.9km[40o]
Speed = d/t = 196.9km/2h = 98.4km/h.
b. V = 196.9km[40o]/2h = 98.4km/h[40o].
= 98.4km/h[50o] E of N.