Asked by andrew
Express the rate of the reaction in terms of the change in concentration of each of the reactants and products.
2D(g)+3E(g)+F(g)>>>>2G(g) + H(g) when D is decreasing at 0.30 MOL/Ls, how fast is (H) increasing?
2D(g)+3E(g)+F(g)>>>>2G(g) + H(g) when D is decreasing at 0.30 MOL/Ls, how fast is (H) increasing?
Answers
Answered by
DrBob222
rate D is 1/2*d(D)/dT which is 1/2*change in (D)/time.
rate E is 1/2*d(E)/dT
rate F is d(F)/dT
etc.
rate = -d(D)/2*dT = -1/2*(0.3) = -0.15 M/s = rate
rate = d(H)/dT = 0.15 M/s
rate E is 1/2*d(E)/dT
rate F is d(F)/dT
etc.
rate = -d(D)/2*dT = -1/2*(0.3) = -0.15 M/s = rate
rate = d(H)/dT = 0.15 M/s
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