f(x) = (1/2)x ln(x^6) (−1, 0)

Question

(a) Find an equation of the tangent line to the graph of f at the given point.

y=

Answer 1

f'=1/2 ln(x^6) + 1/2 x/x^6 * 6x^5
put in x=-1, f' is the slope of the graph at x=-1,0

tangent line:
y=mx + b
0=f'(-1,0) * -1 + b solve for b
then
y=f'(-1,0) x + b is the equation