A Honda Civic travels in a straight line along a road. Its distance x from a stop sign is given as a function of time t by the equation x(t)= α t^2− β t^3, where α = 1.54m/s2 and β = 5.05×10−2m/s^3 .

Question

Calculate the average velocity of the car for the time intervals:

t=0 to t1 = 2.02s .

t=0 to t2 = 4.00s .

t1 = 2.02s to t2 = 4.00s

Thank you!!

Answer 1

avg velocity= (finalvelocity+initialvel)/2

first, find the stop and start velocityies
t(0)
t(2.02)
t(4.00)

I will do one for you, the last one.

avgvel=(v(4.00)+v(2.02))/2