Asked by Delaney
A rectangle has one corner in quadrant I on the graph of y = 9 − x^2,another corner at the origin, and corners on both the positive y-axis and the positive x-axis. As the corner on
y = 9 − x2 changes, a variety of rectangles are obtained.
Express the area A of the rectangles as a function of x.
y = 9 − x2 changes, a variety of rectangles are obtained.
Express the area A of the rectangles as a function of x.
Answers
Answered by
Steve
clearly, each rectangle with upper-right corner at (x,y) has area
a = xy
Since y = 9-x^2, the area is just
a = x(9-x^2)
Not sure what you need to do with that information. The question is a bit vague.
a = xy
Since y = 9-x^2, the area is just
a = x(9-x^2)
Not sure what you need to do with that information. The question is a bit vague.
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