59.0 mL of a 1.60 M solution is diluted to a total volume of 268 mL. A 134-mL portion of that solution is diluted by adding 111 mL of water. What is the final concentration? Assume the volumes are additive.
10 years ago
11 months ago
To find the final concentration of the solution after dilution, we need to use the formula:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution
V1 = initial volume of the solution
C2 = final concentration of the solution
V2 = final volume of the solution
Let's break down the given information:
Initial concentration (C1) = 1.60 M
Initial volume (V1) = 59.0 mL
Final volume (V2) = 268 mL
Volume of solution used for dilution (V3) = 134 mL
Volume of water added (V4) = 111 mL
We can find the volume of the diluted solution (V5) using the equation:
V5 = V1 + V3
V5 = 59.0 mL + 134 mL
V5 = 193 mL
Now, we can calculate the final concentration (C2) using the formula:
C1V1 = C2V2
(1.60 M)(59.0 mL) = C2(193 mL)
C2 = (1.60 M)(59.0 mL) / (193 mL)
C2 ≈ 0.492 M
Therefore, the final concentration of the solution after dilution is approximately 0.492 M.