a man throws a ball of mass 0.5kg vertically upwards with a velocity of 25 m/s.find:[a}the initial momentum of the ball{b}momentum of the ball at the half way mark of the maximum height {given g=10 m/s square}

Answer 1

initial momentum=.5*25 kg m/s

at halfway up, it has lost 1/2 of its energy.
energy then=initial energy.
1/2 m v^2=1/2 *1/2 m 25^2
so v= .7*25
momentum then= .7 of initial momentum