Asked by P
a photocopy store advertises the following prices: 5 cents per copy for the first 20 copies, 4 cents per copy for the 21st through 100th copy, and 3 cents per copy after the 100th copy. Let x be the # of copies, and let y = the total cost of the photocopying. find the equation in the form y = mx+b that tells you the cost of making x copes when x is more than 100.
Answers
Answered by
Damon
20 for 1.00
then 4*.80 = 3.20 for 21 through 100
so
4.20 for 100
y = 4.20 + .03 (x-100)
y = .03 x - 1.20
then 4*.80 = 3.20 for 21 through 100
so
4.20 for 100
y = 4.20 + .03 (x-100)
y = .03 x - 1.20
Answered by
P
Thank you!
Answered by
uthpala
cost for 0 copy to 20 copy =$ 1
cost for 21 copy to 100 copy = 0.04*80 =$ 3.2
cost for 101 copy to 200 copy) = 0.03*100 =$ 3
then cost for 0 copy to 100 copy must be 4.2 dollars and the total cost for 200 copies must be 7.2 dollars.
thus =>
(y- 7.2)/(x-200) = (7.2-4.2)/(200-100)
(y- 7.2)/(x-200) = 0.03
(y- 7.2) = 0.03x - 6
y = 0.03x + 7.2 - 6
y = 0.03 + 1.2
Answered by
Uthpala
Sorry, the answer must be
y = 0.03x + 1.2
y = 0.03x + 1.2
Answered by
David CHIPANDA
Cost of 20 copies= 20x$0.05
=$1
Cost of 80 copies =80x0.04
=$3.20
Cost of 100 and more copies =0.03(x-100)
So our gradient. =0.03
Y=MX+b
Total cost =gradient x no of copies+ constant
4.20=0.03(100)+b
4.20=3+b
1.2=b
Y=0.03x+1.2
=$1
Cost of 80 copies =80x0.04
=$3.20
Cost of 100 and more copies =0.03(x-100)
So our gradient. =0.03
Y=MX+b
Total cost =gradient x no of copies+ constant
4.20=0.03(100)+b
4.20=3+b
1.2=b
Y=0.03x+1.2
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