Question
A sailboat travels 45km eastward at a speed of 20km/hr. The wind then drops, and the boat continues due east with a speed of 15km/hr for 25km.
a.How long did it take the boat to travel 55km?
b. What was the average velocity for the trip?
a.How long did it take the boat to travel 55km?
b. What was the average velocity for the trip?
Answers
Henry
a. T = d1/V1 + d2/V2 = 45/20 + 10/15 = 2.92 Hours.
b. T1 = d1/V1 = 45/20 = 2.25 Hours.
T2 = d2/V2 = 25/15 = 1.67 Hours.
Vavg=(d1+d2)/(T1+T2)=(45+25)/(2.25+1.67)
= 17.86 km/h.
b. T1 = d1/V1 = 45/20 = 2.25 Hours.
T2 = d2/V2 = 25/15 = 1.67 Hours.
Vavg=(d1+d2)/(T1+T2)=(45+25)/(2.25+1.67)
= 17.86 km/h.