Z = (score-mean)/SEm
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability of the Z score. Probability > .50.
The mean height of students in a college is 155 cms and standard deviation is 15. What is the probability that the mean height of 36 students is less than 157 cms
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z=(157-155)/(1.5/√36)
z=4;
z score of 4 in standard normal deviation is 0.99997
or 99.997%
z=4;
z score of 4 in standard normal deviation is 0.99997
or 99.997%