Asked by S
4t-3s^2+s^3 for t=-2 and s=-3
4(-2)-3(-3)^2+(-3)^3
-8-3(-9)+(-27)
-8-(-27)+(-27)=-8
Am I right?
4(-2)-3(-3)^2+(-3)^3
-8-3(-9)+(-27)
-8-(-27)+(-27)=-8
Am I right?
Answers
Answered by
Steve
sorry
(-3)^2 = (-3)(-3) = +9
(-3)^2 = (-3)(-3) = +9
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