Asked by dinesh
a laser printer is placed on a platform that rotates at a rate of 20rev/min. the beam hits a wall 8m away producing a dot of light that moves horizontally along the wall. let tetabe the angle between the bean and producing the line through the search light perpendicular to the wall. how fast is that dot moving when teta = pie/6 ?
Answers
Answered by
Steve
As usual, draw a diagram. If x is the distance of the beam from the perpendicular line to the wall, then
x/8 = tanθ
x = 8tanθ
So,
dx/dt = 8sec^2θ dθ/dt
When θ = π/6 (and that's pi, not pie!!)
dx/dt = 8(4/3)(20*2π) = 1280π/3 m/s
x/8 = tanθ
x = 8tanθ
So,
dx/dt = 8sec^2θ dθ/dt
When θ = π/6 (and that's pi, not pie!!)
dx/dt = 8(4/3)(20*2π) = 1280π/3 m/s
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.