Asked by Ashleigh
What is the osmotic pressure of a solution made from dissolving 60.0g of glucose, C6H12O6, in 450 mL of water at 10.0∘C?
Answers
Answered by
DrBob222
pi = MRT
pi in mm Hg.
You know R (0.08206) and T (remember in kelvin).
M = mols/L solution.
where mols = grams glucose/molar mass glucose and L solution is 0.450
Solve for pi
pi in mm Hg.
You know R (0.08206) and T (remember in kelvin).
M = mols/L solution.
where mols = grams glucose/molar mass glucose and L solution is 0.450
Solve for pi
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