Asked by Victoria
Given the area of the figure, find its perimeter to the nearest tenth.
1. A = 90 ft^2; number of squares: 6.
A: ?
2. A baseball diamond is a square with an area of 8100 square feet. The length of the diagonal of any square is equal to √2 times it's side length. Finds fhe distance from home plate to second base (the length of the diagonal) to the nearest hundredth of a foot.
A: ?
1. A = 90 ft^2; number of squares: 6.
A: ?
2. A baseball diamond is a square with an area of 8100 square feet. The length of the diagonal of any square is equal to √2 times it's side length. Finds fhe distance from home plate to second base (the length of the diagonal) to the nearest hundredth of a foot.
A: ?
Answers
Answered by
Damon
90/6 = 15 ft^2 each
so the side of each square is sqrt 15
2 sqrt 15 + 3 sqrt 15 + 2 sqrt 15 + 3 sqrt 15 :)
so the side of each square is sqrt 15
2 sqrt 15 + 3 sqrt 15 + 2 sqrt 15 + 3 sqrt 15 :)
Answered by
Damon
sqrt 8100 = 90 ft baselines
so 90 sqrt 2
so 90 sqrt 2
Answered by
Victoria
1. The perimeter of the figure is 54. 2 ft.?
2. The length from home plate to second base is 127. 28 ft.?
2. The length from home plate to second base is 127. 28 ft.?
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