Asked by shonta
The area of a rectangle is
77 yd2
, and the length of the rectangle is
10 yd
less than three times the width. Find the dimensions of the rectangle.
77 yd2
, and the length of the rectangle is
10 yd
less than three times the width. Find the dimensions of the rectangle.
Answers
Answered by
PsyDAG
L = 3W - 10
LW = (3W-10)W = 3W^2 - 10W = 77
3W^2 - 10W - 77 = 0
Solve quadratic equation for W, then L.
LW = (3W-10)W = 3W^2 - 10W = 77
3W^2 - 10W - 77 = 0
Solve quadratic equation for W, then L.
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