Asked by mohsin
bottle of hcl which is 40 mass%and has density of 1.20g /ml. calculate ml to be taken from this bottle to prepare 500 ml solution of 0.2 M
Answers
Answered by
DrBob222
First, determine the molarity of the solution of HCl and
Second, use the dilution formula.
1.20 g/mL x 1000 mL x 0.40 x (1 mol/36.5g) = 13.15 which I would round to 13.2 M
Then c1v1 = c2v2
13.2*v1 = 0.2M x 500 mL
Solve for v1.
You can do the M of the initial HCl solution another way.
40% by mass means 40g HCl/100 g solution.
40 g is how many mols? That's mols = grams/molar mass = 40/36.5 = 1.096 mols in 100 g solution. What's the volume of the solution (the 100g?). That's mass = volume x density or volume = mass/density = 100g/1.20 = 83.33 mL or 0.08333 L, so M = mols/L = 1.096/0.083333 = 13.15 which rounds to 13.2,
Second, use the dilution formula.
1.20 g/mL x 1000 mL x 0.40 x (1 mol/36.5g) = 13.15 which I would round to 13.2 M
Then c1v1 = c2v2
13.2*v1 = 0.2M x 500 mL
Solve for v1.
You can do the M of the initial HCl solution another way.
40% by mass means 40g HCl/100 g solution.
40 g is how many mols? That's mols = grams/molar mass = 40/36.5 = 1.096 mols in 100 g solution. What's the volume of the solution (the 100g?). That's mass = volume x density or volume = mass/density = 100g/1.20 = 83.33 mL or 0.08333 L, so M = mols/L = 1.096/0.083333 = 13.15 which rounds to 13.2,
Answered by
chem mistary
wrong question
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.