Asked by Christie
consider the vector F1: (27N,20°)The angles are measured from the positive x axis with the counter-clockwise angular direction taken as positive.
Consider the vector:F2=-F1
What is in degrees as measured from the positive x in the counter-clockwise angular direction the direction of vector F2?
*I have tried using the formula arctan (y/x)+ 180 but it keeps telling me I am incorrect. I would love it if anyone could give me some guidance on this.
Consider the vector:F2=-F1
What is in degrees as measured from the positive x in the counter-clockwise angular direction the direction of vector F2?
*I have tried using the formula arctan (y/x)+ 180 but it keeps telling me I am incorrect. I would love it if anyone could give me some guidance on this.
Answers
Answered by
Henry
F1 = 27N[20o] = 27*cos20 + i27*sin20 =
25.37 + 9.23i.
F2 = -27N[20o] = -27*cos20 - 27*sin20 =
-25.37 - -9.23i
Tan Ar = Y/X = -9.23/-25.37 = 0.36382
Ar = 20o = Reference Angle.
Since X and Y are both negative, we are in the 3rd Quad.
A = 20 + 180 = 200o = The direction of
F2.
25.37 + 9.23i.
F2 = -27N[20o] = -27*cos20 - 27*sin20 =
-25.37 - -9.23i
Tan Ar = Y/X = -9.23/-25.37 = 0.36382
Ar = 20o = Reference Angle.
Since X and Y are both negative, we are in the 3rd Quad.
A = 20 + 180 = 200o = The direction of
F2.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.