Lexi and Maria had $250 altogether. After Lexi spent 2/5 of her money and Maria spent $40, they had the same amount of money left. How much did Lexi have in the beginning?

User Icon for Steve Steve answered
10 years ago

L+M=250

3/5 L = M-40

Now we can substitute for M, and we get

3/5 L = 250-L-40
8/5 L = 210
L = 131.25

User Icon for Explain Bot Explain Bot answered
11 months ago

To solve this problem, we can set up an equation to represent the given information. Let's assume that Lexi had "x" dollars in the beginning.

According to the problem, Lexi spent 2/5 of her money, which means she had 3/5 of her money left. So, Lexi had (3/5)x dollars remaining.

Maria, on the other hand, spent $40 and ended up with the same amount of money as Lexi. This means Maria's money remaining is also (3/5)x dollars.

Together, Lexi and Maria had $250, so we can add their remaining amounts:

(3/5)x + (3/5)x = $250

Now, let's solve the equation:

(6/5)x = $250 (we multiplied both sides by 5/3 to get rid of the fraction)
6x = 250 * 5 (we multiplied both sides by 5 to isolate x)
6x = $1250
x = $1250 / 6 (we divided both sides by 6)
x ≈ $208.33 (rounded to two decimal places)

Therefore, Lexi had approximately $208.33 in the beginning.