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There were 409 tickets sold for a basketball game. The activity card holder's ticket cost $ 1.75, and the non-card holder's tic...Asked by cori
There were 654 tickets sold for a basketball game. The activity cardholders' tickets cost 1.5 and the non-cardholders' tickets cost 2.00. the total amount of money collected was 1171.50. how many of each kind of tickets were sold.
Answers
Answered by
Marianne
x = activity cardholders
y = non-cardhoolders
x + y = 654 tickets
1.50x + 2.00y = 1171.50
x = 654 - y
1.50(654-y) + 2.00y = 1171.50
981 - 1.50y + 2.00y = 1171.50
981 + .50y = 1171.50
.50y = 190.5
y = 381
x + 381 = 654
x = 273
273 activity cardholders
381 non-cardholders
273(1.50) + 381(2.00) = 1171.50
409.50 + 762 = 1171.50
1171.5 = 1171.50
y = non-cardhoolders
x + y = 654 tickets
1.50x + 2.00y = 1171.50
x = 654 - y
1.50(654-y) + 2.00y = 1171.50
981 - 1.50y + 2.00y = 1171.50
981 + .50y = 1171.50
.50y = 190.5
y = 381
x + 381 = 654
x = 273
273 activity cardholders
381 non-cardholders
273(1.50) + 381(2.00) = 1171.50
409.50 + 762 = 1171.50
1171.5 = 1171.50
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