Asked by Alfred
I've been stuck on a problem with my homework for a couple of minutes now. We are doing Systems of Two Equations, using the substitution method. The problem is:
4y-6x+20=0
3=(18/5)x+(21/10)y
4y-6x+20=0
3=(18/5)x+(21/10)y
Answers
Answered by
Steve
well, from the first equation,
y = (6x-20)/4
Substitute that into the second and you have
3 = (18/5)x + (21/10)(6x-20)/4
x = 2
So, y = -2
y = (6x-20)/4
Substitute that into the second and you have
3 = (18/5)x + (21/10)(6x-20)/4
x = 2
So, y = -2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.