Question
How would I make 500 ml's of a .35M NaCI solution. MW= 58.44
( I know how to do the first part)
How many micromoles of NaCI would be present in that solution?
What would be the percentage of NaCI in that solution?
( I know how to do the first part)
How many micromoles of NaCI would be present in that solution?
What would be the percentage of NaCI in that solution?
Answers
DrBob222
How many mols do you want? That's M x L = 0.35 x 0.500 = 0.175 mols.
Then grams = mols x molar mass = 0.175 x 58.44 = approx 10.3 grams NaCl but you need to get a more accurate number.
b. There are 0.175 mol and that x 1E6 to give micromoles.
c. % what? w/w; w/v; ? I will assume you want % mass/volume
%NaCl = grams NaCl/100 g solution
You have approx 10.3g in 500 mL or
(10.3g/500)*100 = % w/v
Then grams = mols x molar mass = 0.175 x 58.44 = approx 10.3 grams NaCl but you need to get a more accurate number.
b. There are 0.175 mol and that x 1E6 to give micromoles.
c. % what? w/w; w/v; ? I will assume you want % mass/volume
%NaCl = grams NaCl/100 g solution
You have approx 10.3g in 500 mL or
(10.3g/500)*100 = % w/v
frank
thanks that is exactly how the teacher gave us the questions