vf1=2.84t
vf2=vf1+a2*t
but vf2=2.4*2.84t
2.4*2.84t=2.84t+a2 t
divide out t, and solve for a2. Check my thinking.
An automobile starts from rest and accelerates to a final velocity in two stages along a straight road. Each stage occupies the same amount of time. In stage 1, the magnitude of the car's acceleration is 2.84 m/s2. The magnitude of the car's velocity at the end of stage 2 is 2.40 times greater than it is at the end of stage 1. Calculate the magnitude of the acceleration in stage 2.
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