Asked by jojo
The vapor pressure of ethanol is 54.68 mm Hg at 25oC.
How many grams of chlorophyll , C55H72MgN4O5, a nonvolatile, nonelectrolyte (MW = 893.5 g/mol), must be added to 207.6 grams of ethanol to reduce the vapor pressure to 53.60 mm Hg ?
ethanol = CH3CH2OH = 46.07 g/mol.
How many grams of chlorophyll , C55H72MgN4O5, a nonvolatile, nonelectrolyte (MW = 893.5 g/mol), must be added to 207.6 grams of ethanol to reduce the vapor pressure to 53.60 mm Hg ?
ethanol = CH3CH2OH = 46.07 g/mol.
Answers
Answered by
DrBob222
delta P = 54.68-53.60 = 1.08 mm
delta P = 1.08 = Xchlor*P<sup>o</sup><sub>solvent</sub>
1.08 = Xchlor*54.68
Solve for X chlorophyll
Then Nc = mols chlorophyll
and Netoh = mols ethanol
(Nc)/(Nc+Netoh) = X chlorophyll from above.
Solve for Nc
Then convert to grams.
g chlorophyll = mols chlorophyll x molar mass chlorophyll.
Post your work if you get stuck.
delta P = 1.08 = Xchlor*P<sup>o</sup><sub>solvent</sub>
1.08 = Xchlor*54.68
Solve for X chlorophyll
Then Nc = mols chlorophyll
and Netoh = mols ethanol
(Nc)/(Nc+Netoh) = X chlorophyll from above.
Solve for Nc
Then convert to grams.
g chlorophyll = mols chlorophyll x molar mass chlorophyll.
Post your work if you get stuck.
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