Asked by Anonymous

isosceles trapezoid
with a perimeter of 52 meters; one base is 10 meters greater than the other base; the measure of each leg is 3 less than twice the base of the shorter base

Answers

Answered by Steve
if the shorter base is b, then we have

b + b+10 + 2(2b-3) = 52

Now just solve for b and then the other base and legs.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions