Asked by Anonymous
isosceles trapezoid
with a perimeter of 52 meters; one base is 10 meters greater than the other base; the measure of each leg is 3 less than twice the base of the shorter base
with a perimeter of 52 meters; one base is 10 meters greater than the other base; the measure of each leg is 3 less than twice the base of the shorter base
Answers
Answered by
Steve
if the shorter base is b, then we have
b + b+10 + 2(2b-3) = 52
Now just solve for b and then the other base and legs.
b + b+10 + 2(2b-3) = 52
Now just solve for b and then the other base and legs.
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