Asked by DickinsonW
Propylene (or propene in proper IUPAC nomenclature), H2C=CH-CH3, can be reacted by addition polymerization to form polypropylene (PP). The process is initiated with the radical, I*.
Choose the image above that properly indicated the location of the unpaired electron, *.
What is the degree of polymerization, n, of PP with a molecular weight of 3.091e5 g/mol?
Choose the image above that properly indicated the location of the unpaired electron, *.
What is the degree of polymerization, n, of PP with a molecular weight of 3.091e5 g/mol?
Answers
Answered by
Will
what image?
degree of polymerization is like this
propylene is H2C=CH-CH3 so 3C and 6C
molec. weigth (12*3)+6 = 42 g/mol
n = 3.091*10^5 / 42 = 7359.52
degree of polymerization is like this
propylene is H2C=CH-CH3 so 3C and 6C
molec. weigth (12*3)+6 = 42 g/mol
n = 3.091*10^5 / 42 = 7359.52
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