Asked by james

A ship at sea is due into a port 600 km due south in two days. However, a severe storm comes in and blows it 200 km due east from its original position. How far is the ship from its destination?
Answered by Steve
d^2 = 600^2 + 200^2
Answered by Henry
X = 200 km.
Y = -600 km.

d^2=X^2 + Y^2=200^2 + (-600)^2=400,000
d = 632 km.
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