Asked by Joe

The figure below shows an electron passing between two charged metal plates that create an 115 N/C vertical electric field perpendicular to the electron’s original horizontal velocity. (These can be used to change the electron’s direction, such as in an oscilloscope.) The initial speed of the electron is 3.30×106 m/s, and the horizontal distance it travels in the uniform field is 4.10 cm. What is its vertical deflection?
Answered by Joe
If two equal charges each of 1.0 C each are separated in air by a distance of 1.0 km, what is the magnitude of the force acting between them? You will see that even at a distance as large as 1.0 km, the repulsive force is substantial because 1.0 C is a very significant amount of charge.
Answered by bobpursley
On the second question, this is coulombs law. I don't understand what your question is, or what you don't understand about it.

On the first, Force=qE
then find the time it is in the field
time=distancetraveled/velocity

Now you have the force, and time in the force,
distance=1/2 (force/mass)time^2
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