Asked by Nay
I need to find expressions that will show how 5 x 37 can be rewritten using distributive property.
5 x 30 + 7 ---- My answer
5 x 30 + 5 x 7
5 x 40 - 5 x 7
5 x 40 - 5 x 3
*It can be more than one answer*
3u + 7v + 4u = 2v (I have to simplify)
My answer is 7u + 9v because 4+3 and 7 + 2
7u + 5v
&u + 9v
10u - 2v
12uv
5 x 30 + 7 ---- My answer
5 x 30 + 5 x 7
5 x 40 - 5 x 7
5 x 40 - 5 x 3
*It can be more than one answer*
3u + 7v + 4u = 2v (I have to simplify)
My answer is 7u + 9v because 4+3 and 7 + 2
7u + 5v
&u + 9v
10u - 2v
12uv
Answers
Answered by
Bosnian
37 = 30 + 7
5 x 37 = 5 x ( 30 + 7 ) = 5 x 30 + 5 x 7
3 u + 7 v + 4 u = 2 v Subtract 2 v to both sides
3 u + 7 v + 4 u - 2 v = 2 v - 2 v
3 u + 4 u + 7 v - 2 v = 0
7 u + 5 v = 0
5 x 37 = 5 x ( 30 + 7 ) = 5 x 30 + 5 x 7
3 u + 7 v + 4 u = 2 v Subtract 2 v to both sides
3 u + 7 v + 4 u - 2 v = 2 v - 2 v
3 u + 4 u + 7 v - 2 v = 0
7 u + 5 v = 0
Answered by
Ms. Sue
No.
Remember PEMDAS
http://www.mathsisfun.com/operation-order-pemdas.html
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7u = -5v
Remember PEMDAS
http://www.mathsisfun.com/operation-order-pemdas.html
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
7u = -5v
Answered by
Bosnian
AND
37 = 40 - 3
5 x 37 = 5 x ( 40 - 3 ) = 5 x 40 - 5 x 3
37 = 40 - 3
5 x 37 = 5 x ( 40 - 3 ) = 5 x 40 - 5 x 3
Answered by
Nay
Thank You! :)
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